stem cells :: essays research papers

Advancements in genetic engineering has been one of the most talked about subjects for many years. It has scared some but at the same time intrigued others. This question how far is too far, will play a big issue in years to come and even now for that mater. What people do not understand is that the research that is being done today is being done to help cure incurable diseases like the Aids virus and Cancer and it is not being done to create at perfect utopian society where everyone is the same and equal in all aspects. Stem cell research has been around since the early 1980's and since its development many advances have been made. In the beginning they could only speculate what they could do with the cells. They have come farther than anyone cold imagine when they cloned dolly the sheep in 1997 and since then it has become a popular subject. People fore the most part are open to the idea that stem cells could be the cure for many diseases but it scares them to thing that since scientists can change the cells in a kidney that why couldn't they manipulate the cells to make a perfect human. Though the argument is sound and logical it is unlikely that in the near future of ever for that matter that our government would allow such things to happen. Though the slow downward spiral of the development of stem cells is inevitable it is not of any real threat to our generation. President Bush's views on stem cell research are probably the best way to go about studying the cells without the most complications. In 2001 he proposed that only some cells be researched. CNN put it this way, "The president said scientists have told him that research on the 60 exist ing stem cell lines has great promise that could lead to breakthrough therapies and cures. This allows us to explore the promise and potential of stem cell research without crossing a fundamental moral line"(cnn.com). This is probably the most practical way of looking at the research but recently Bush changed his policy on government funding of Stem Cell research. His new policy allows the development of stem cells to continue but now cuts government funding from the picture. Ken Lisaius the

Effects of Social Networking Sites on Student’s Life. Essay

Students! The Builders of Nation ! In today’s life as the world is developing rapidly, the youth becoming stronger in each sense. The technologies are reaching at their peak. Dr. Abdul Kalam has said that India would be the ‘Developed Country’ upto 2020. He has dreamed about ‘Developed India’ which will be possible through his ‘Mission 2020’ towards India. He believes that Indian youth is the source for that dream. Mark Zuckerberg and Jack Dorsey are the two innovative people of 21st century as they have innovated social networking communication sites such as facebook and twitter respectively. Social networking sites such as facebook and twitter are few of the revolutionary inventions of decade. These are mostly popular in the college students. Actually it is proved that it is good mean of communication among them and is the best way of their time to be passed quiet easily. College students are heavy users of these sites through internet compared to the general population. It is the part of their daily communication habits. Social networking sites highly benefits students academically. The various features of different sites give flexibility to students to be a part of social level with others. Students can relate and share with those who have a common interest and ability to make connection with like-minded students, build relationships and communication among them. Social networking sites are the part of modern technology and students are making use of it in different ways. These sites help them to search material which they needs online. It makes them quite easy way to search and get the needful things. Besides this all; there are some negative effects on them as well. Students are losing in the real world by sticking to these social networking sites. The popularity of these sites increased rapidly in the last decade. This is probably due to reason that college students used it extensively to get global access. Sites like facebook and twitter have become a craze for everyone nowadays. These sites have caused potential harm to society. Students are becoming victims of such sites this is because of reason that when they are studying or searching their course material online; they get attracted to these sites to kill the burden in their study time, diverting their attention from their work. They prefer their concentration more on these sites than regular study. Students have started relying more on the information accessible easily on these sites. This reduces their learning and research capabilities. These sites cause reduction in their academic performance and concentration to study well. It reduces their communication skill with others. It also reduces command over language use and creative writing skills. Students mostly use slang words or shortened forms of words on these sites. They start relying on the computer grammar and spelling. Ultimately; it depends on each and every individual how much he involved in these kinds of things. Each individual should decide weathers it is good or bad for him. One should always pick positive things from it. It will have good advantage for him as well as his career. As we want to see ‘Developed India’; is youth in right path? As the craze of networking sites going in negative direction and increasing; the question mark on ‘Mission 2020’ is being much stronger. It’s time to think positively and taking part in transforming India.

A Comparative Study of the Efficacy of Pilates and Acupuncture

Chronic low back pain is the diagnosis for individuals who have been suffering from acute back pain but have not showed any signs of improving.In a manner of speaking, chronic low back pain occurs when an individual’s acute back pain has reached the duration of 91 days without improvement (Bogduk & McGuirk, 2002). Chronic low back pain has various treatments, and this research aims to determine which is appropriate.According to Colleen Craig (2001), pilates exercises abdominal muscles, and one of these abdominal muscles, if properly attended to, can prevent chronic low back pain. Acupuncture, on the other hand, is also used for the treatment of low back pain (Liao, Lee, & Ng, 1994).Problem Statement and HypothesisThis study intends to determine whether or not pilates and acupuncture produce better results than that of traditional lumbar stabilization exercises for the treatment of chronic low back pain. The hypothesis of this research is that alternative methods, such as pilat es and acupuncture, are superior over the traditional lumbar stabilization exercises in treating chronic low back pain.AssumptionFor this research, it is assumed that pilates and acupuncture produce better results than that of the traditional lumbar stabilization exercises when it comes to treating patients with chronic low back pain.Purpose and SignificanceThis study aims to compare other modes of therapy to the traditional lumbar stabilization exercises and to determine whether other modes of therapy, specifically pilates and acupuncture, can help improve the conditions of patients who have chronic low back pain.The significance of the study is that it can provide information about which physical therapy is appropriate for individuals who have chronic low back pain. New information about various treatments can help enhance physical therapy and produce better results.Nature of Study and Theoretical FrameworkAn integration of quantitative and qualitative methods will be conducted th roughout the course of the study. The use of quantitative methods is vital for these will determine the empirical data that will contribute to the accuracy of the study. On the other hand, through the use of qualitative methods, the study will be able to provide insight on what the patients think of the aforementioned treatments.Research QuestionsThis study aims to address the following:Which treatment is more effective in the treatment of chronic low back pain? Why is the treatment more effective than the other treatments? What are the pros and cons of alternative treatments for chronic low back pain?   Definition of TermsChronic back pain – the condition wherein the individual has been suffering from acute back pain and has not shown any signs of improving after the duration of 91 days (Bogduk & McGuirk, 2002).Pilates – a â€Å"system of exercises† (Breibart, 2005, p. 3) that helps to stretch and strengthen the body as well as improve its posture and tone (B reibart, 2005).Acupuncture – the insertion of â€Å"hair-fine needles† (Tierney, 1999, p. 1) into certain areas of the body in order to stimulate the healing capacity of the individual’s body (Tierney, 1999).

Experiment 1: Calorimetry

Experiment 1: Calorimetry Nadya Patrica E. Sauza, Jelica D. Estacio Institute of Chemistry, University of the Philippines, Diliman, Quezon City 1101 Philippines Results and Discussion Eight Styrofoam ball calorimeters were calibrated. Five milliliters of 1M hydrochloric acid (HCl) was reacted with 10 ml of 1M sodium hydroxide (NaOH) in each calorimeter. The temperature before and after the reaction were recorded; the change in temperature (? T) was calculated by subtracting the initial temperature from the final temperature. The reaction was performed twice for every calorimeter. The heat capacity (Ccal) of each calorimeter was calculated using the formula, C_cal=(- H? _rxn^o n_LR)/? T[1] where ? Horxn is the total heat absorbed or evolved for every mole of reaction and nLR is the number of moles of the limiting reactant. The ? Horxn used was -55. 8kJ per mole of water while the nLR was 0. 005 mole. Table 1. Average Ccal from recorded ? T values. Trial? T, (oC)Ccal, (J)Ave Ccal, (J) 112. 2126. 82202. 91 21. 0279. 00 213. 093. 00108. 50 22. 3124. 00 310. 5558. 00558. 00 20. 5558. 00 412. 0139. 50244. 13 20. 8348. 75 513. 093. 0081. 38 24. 069. 75 612. 0139. 50209. 25 21. 0279. 00 712. 111. 60111. 60 22. 5111. 60 813. 093. 00116. 25 22. 0139. 50 Different heat capacities were calculated for each calorimeter (Table 1). After calibration, a reaction was performed in a calorimeter by each pair. A total of eight reactions were observed by the whole class. The temperature before and after the reaction were recorded. Then the change in temperature was calculated. Eac h reaction was performed twice to produce two trials. The experimental ? Horxn for each reaction was solved using the formula, H? _rxn^o=(-C_cal ? T)/n_LR [2] where Ccal is the heat capacity previously calculated for each calorimeter. The percent error for each reaction was computed by comparing the computed experimental ? Horxn to the theoretical ? Horxn using the formula, % error=|(computed-theoretical)/theoretical|? 100% [3] Table 2. Comparison of calculated ? Horxn and theoretical ? Horxn. RxnLRTrial? T, (oC)? Horxn, (kJ/mol)Ave ? Horxn, (kJ/mol)Theo ? Horxn, (kJ/mol)% Error 1HCl13. 5-142. 04-131. 89-132. 510. 47 23. 0-121. 75 2HOAc11. 3-26. 34-41. 61-56. 0924. 65 22. 7-56. 89 3HOAc11. 8-189. 61-203. 16-52. 47287. 18 22. 0-216. 70 4HNO311. 5-73. 24-70. 80-55. 8426. 78 21. 4-68. 36 5Mg13. 0-118. 67-138. 45-466. 8570. 34 24. 0-158. 23 6Mg15. 5-559. 4-635. 72-953. 1133. 30 27. 0-712. 01 7Zn13. 0-43. 80-43. 80-218. 6679. 97 23. 0-43. 80 8CaCl210. 00. 00-5. 8113. 07144. 47 20. 5-11. 63 There were differences in experimental and theoretical values of ? Horxn as shown by the percent error for each reaction (table 2). The discrepancies were caused by many factors. One factor was the loss of heat. The heat may have bee n released when the thermometer was pushed or pulled during the reaction. The heat may also have been lost because the calorimeter is not totally isolated. Another factor was the dilution of the solution. The pipette or test tube may still have been wet when used. However, the concentration used in solving for values was the concentration of the undiluted solution. Another factor that may have contributed to the difference in the experimental and theoretical values was human error. It was manifested when reading the thermometer or measuring chemicals with different instruments. The factors aforementioned are the limitations of this experiment. References Petrucci, R. H. ; Herring, F. G. ; Madura, J. D. ; Bissonnette, C. General Chemistry, 10th ed. ; Pearson Education: Canada, 2011; Chapter 7. Appendices Appendix A Comparison of Observed and Theoretical Heats of Reactions RxnLRTrial? TnLRqrxn? HorxnAve ? HorxnTheo ? Horxn% Error 1HCl13. 500. 00500-710. 19-142. 04-131. 89-132. 510. 47 23. 000. 00500-608. 73-121. 75 2HOAc11. 250. 00515-135. 63-26. 34-41. 61-56. 0924. 65 22. 700. 00515-292. 95-56. 89 3HOAc11. 750. 00515-976. 50-189. 61-203. 16-52. 47287. 18 22. 000. 00515-1116. 00-216. 70 4HNO311. 500. 00500-366. 19-73. 24-70. 80-55. 8426. 78 21. 400. 00500-341. 78-68. 36 5Mg13. 000. 00206-244. 13-118. 67-138. 45-466. 8570. 34 24. 000. 00206-325. 50-158. 23 6Mg15. 500. 00206-1150. 88-559. 44-635. 72-953. 1133. 30 27. 000. 00206-1464. 75-712. 01 7Zn13. 000. 00764-334. 80-43. 80-43. 80-218. 6679. 97 23. 000. 00764-334. 80-43. 0 8Na2CO3/ CaCl210. 000. 005000. 000. 00-5. 8113. 07144. 47 20. 500. 00500-58. 13-11. 63 Appendix B Sample Calculations Calibration of Calorimeter 10ml 1M NaOH + 5ml 1M HCl n. i. e. : OH-(aq) + H+(aq) ? H2O(l)? Horxn= -55. 8kJ LR: HCLnLR= 0. 005mol Grp 1 Trial 1 ?T= 2. 2oC Sol’n: C_cal=(- H? _rxn^o n_LR)/? T C_cal=(-(-55. 8kJ)(0. 005mol))/(? 2. 2? ^ o C)? 1000J/1kJ ?(C_cal=126. 82 J) Determination of Heats of Reaction Neutralization Reaction Rxn 4 Trial 1: 10ml 1M NaOH + 5ml 1M HNO3 n. i. e. : OH-(aq) + H+(aq) ? H2O(l) LR: HNO3nLR= 0. 005mol ?T= 1. 5oCCcal= 244. 125 J Sol’n H? _rxn^o=(-C_cal ? T)/n_LR H? _rxn^o=(-(244. 25J)(? 1. 5? ^o C))/0. 005mol? 1kJ/1000J ? ( H? _rxn^o=-73. 24kJ) Reaction between an Active Metal and an Acid Rxn 5 Trial 1: 15ml 1M HCl+ 0. 05g Mg n. i. e. : 2H+(aq) + Mg(s) ? Mg+2(aq) + H2(g) LR: MgnLR= 0. 00206mol ?T= 3oCCcal= 81. 375 J Sol’n H? _rxn^o=(-C_cal ? T)/n_LR H? _rxn^o=(-(81. 375J)(3^o C))/0. 00206mol? 1kJ/1000J ?( H? _rxn^o=-118. 67kJ) Displacement of One Metal by Another Rxn 7 Trial 1: 15ml 1M CuSO4 + 0. 5g Zn n. i. e. : Cu+2(aq) + Zn(s) ? Zn+2(aq) + Cu(s) LR: ZnnLR= 0. 00764mol ?T= 3oCCcal= 111. 6 J Sol’n H? _rxn^o=(-C_cal ? T)/n_LR H? _rxn^o=(-(111. 6J)(3^o C))/0. 00764mol? 1kJ/1000J ?( H? rxn^o=-43. 80kJ) Precipitation Reaction Rxn 8 Trial 1: 10ml 0. 5M Na2CO3 + 5ml 1M CaCl2 n. i. e. : CO3-2(aq) + Ca+2(aq) ? CaCO3(s) LR: Na2CO3/ CaCl2nLR= 0. 005mol ?T= 0. 5oCCcal= 116. 25 J Sol’n H? _rxn^o=(-C_cal ? T)/n_LR H? _rxn^o=(-(116. 25J)(? 0. 5? ^o C))/0. 005mol? 1kJ/1000J ? ( H? _rxn^o=-11. 63kJ) Appendix C Answers to the Questions in the Lab Manual There are many possibilities that explain the discrepancy of the experimental and theoretical values of ? Horxn. First, heat might have been lost to the surroundings. This is possible whenever the thermometer is pulled out or pushed in the calorimeter during the reaction. Also, the calorimeter might not have been thoroughly isolated. Second, the solution might have been diluted in the test tube or pipette. They might have been wet when used with the solution. Lastly, the discrepancies might have occurred due to human error. The students might have misread the thermometer when taking the temperature or the pipette when measuring the solutions. a. It is important to keep the total volume of the resulting solution to 15ml because any more or any less than that of the volume can contribute to the absorption or release of additional heat therefore affecting the ? Horxn. b. It is important to know the exact concentrations of the reactants to solve for their number of moles and to find out the limiting reactant. c. It is important to know the exact weight of the metal solids used to solve for their number of moles and to find out whether one of them is a limiting reactant. Also, the weight is needed to solve for the heat capacity of the solid when the specific heat is given. 200ml 0. 5M HA + NaOH ? -6. 0kJ LR: HAnLR= 0. 1mole H? _(rxn,mol)^o= (-6. 0 kJ)/(0. 1 mol) ?( H? _(rxn,mol)^o= -60 kJ) HA is a strong acid. OH-(aq) + H+(aq) ? H2O(l)? Horxn= -60 kJ/mole Calibration:15ml 2. M HCl + 5ml 2. 0M NaOH? T=5. 60oC LR: NaOHnLR= 0. 01mole Reaction:20ml 0. 450M CuSO4 + 0. 264g Zn? T=8. 83oC LR: ZnnLR= 0. 00404mole n. i. e. : OH-(aq) + H+(aq) ? H2O(l) n. i. e. : Cu+2(aq) + Zn(s) ? Zn+2(aq) + Cu(s) C_cal=(- H? _rxn^o n_LR)/? T C_cal=(-(-55. 8kJ)(0. 01mol))/(? 5. 60? ^o C)? 1000J/1kJ ?(C_cal=99. 6 J) H? _rxn^o=(-C_cal ? T)/n_LR H? _rxn^o=(-(99. 6J)(? 8. 83? ^o C))/0. 00404mol? 1kJ/1000J ? ( H? _rxn^o=-218. 0 kJ) OH-(aq) + H+(aq) ? H2O(l)? Horxn= -55. 8kJ ?Hof,H2O= -285 kJ ?Hof,OH-= ? ?Horxn= ? Hof,product – ? Hof,reactant -55. 8 kJ = ? Hof,OH- – (-285 kJ) ?( H? _(f,? OH? ^-)^o=-218. 0 kJ) Experiment 1: Calorimetry Experiment 1: Calorimetry Nadya Patrica E. Sauza, Jelica D. Estacio Institute of Chemistry, University of the Philippines, Diliman, Quezon City 1101 Philippines Results and Discussion Eight Styrofoam ball calorimeters were calibrated. Five milliliters of 1M hydrochloric acid (HCl) was reacted with 10 ml of 1M sodium hydroxide (NaOH) in each calorimeter. The temperature before and after the reaction were recorded; the change in temperature (? T) was calculated by subtracting the initial temperature from the final temperature. The reaction was performed twice for every calorimeter. The heat capacity (Ccal) of each calorimeter was calculated using the formula, C_cal=(- H? _rxn^o n_LR)/? T[1] where ? Horxn is the total heat absorbed or evolved for every mole of reaction and nLR is the number of moles of the limiting reactant. The ? Horxn used was -55. 8kJ per mole of water while the nLR was 0. 005 mole. Table 1. Average Ccal from recorded ? T values. Trial? T, (oC)Ccal, (J)Ave Ccal, (J) 112. 2126. 82202. 91 21. 0279. 00 213. 093. 00108. 50 22. 3124. 00 310. 5558. 00558. 00 20. 5558. 00 412. 0139. 50244. 13 20. 8348. 75 513. 093. 0081. 38 24. 069. 75 612. 0139. 50209. 25 21. 0279. 00 712. 111. 60111. 60 22. 5111. 60 813. 093. 00116. 25 22. 0139. 50 Different heat capacities were calculated for each calorimeter (Table 1). After calibration, a reaction was performed in a calorimeter by each pair. A total of eight reactions were observed by the whole class. The temperature before and after the reaction were recorded. Then the change in temperature was calculated. Eac h reaction was performed twice to produce two trials. The experimental ? Horxn for each reaction was solved using the formula, H? _rxn^o=(-C_cal ? T)/n_LR [2] where Ccal is the heat capacity previously calculated for each calorimeter. The percent error for each reaction was computed by comparing the computed experimental ? Horxn to the theoretical ? Horxn using the formula, % error=|(computed-theoretical)/theoretical|? 100% [3] Table 2. Comparison of calculated ? Horxn and theoretical ? Horxn. RxnLRTrial? T, (oC)? Horxn, (kJ/mol)Ave ? Horxn, (kJ/mol)Theo ? Horxn, (kJ/mol)% Error 1HCl13. 5-142. 04-131. 89-132. 510. 47 23. 0-121. 75 2HOAc11. 3-26. 34-41. 61-56. 0924. 65 22. 7-56. 89 3HOAc11. 8-189. 61-203. 16-52. 47287. 18 22. 0-216. 70 4HNO311. 5-73. 24-70. 80-55. 8426. 78 21. 4-68. 36 5Mg13. 0-118. 67-138. 45-466. 8570. 34 24. 0-158. 23 6Mg15. 5-559. 4-635. 72-953. 1133. 30 27. 0-712. 01 7Zn13. 0-43. 80-43. 80-218. 6679. 97 23. 0-43. 80 8CaCl210. 00. 00-5. 8113. 07144. 47 20. 5-11. 63 There were differences in experimental and theoretical values of ? Horxn as shown by the percent error for each reaction (table 2). The discrepancies were caused by many factors. One factor was the loss of heat. The heat may have bee n released when the thermometer was pushed or pulled during the reaction. The heat may also have been lost because the calorimeter is not totally isolated. Another factor was the dilution of the solution. The pipette or test tube may still have been wet when used. However, the concentration used in solving for values was the concentration of the undiluted solution. Another factor that may have contributed to the difference in the experimental and theoretical values was human error. It was manifested when reading the thermometer or measuring chemicals with different instruments. The factors aforementioned are the limitations of this experiment. References Petrucci, R. H. ; Herring, F. G. ; Madura, J. D. ; Bissonnette, C. General Chemistry, 10th ed. ; Pearson Education: Canada, 2011; Chapter 7. Appendices Appendix A Comparison of Observed and Theoretical Heats of Reactions RxnLRTrial? TnLRqrxn? HorxnAve ? HorxnTheo ? Horxn% Error 1HCl13. 500. 00500-710. 19-142. 04-131. 89-132. 510. 47 23. 000. 00500-608. 73-121. 75 2HOAc11. 250. 00515-135. 63-26. 34-41. 61-56. 0924. 65 22. 700. 00515-292. 95-56. 89 3HOAc11. 750. 00515-976. 50-189. 61-203. 16-52. 47287. 18 22. 000. 00515-1116. 00-216. 70 4HNO311. 500. 00500-366. 19-73. 24-70. 80-55. 8426. 78 21. 400. 00500-341. 78-68. 36 5Mg13. 000. 00206-244. 13-118. 67-138. 45-466. 8570. 34 24. 000. 00206-325. 50-158. 23 6Mg15. 500. 00206-1150. 88-559. 44-635. 72-953. 1133. 30 27. 000. 00206-1464. 75-712. 01 7Zn13. 000. 00764-334. 80-43. 80-43. 80-218. 6679. 97 23. 000. 00764-334. 80-43. 0 8Na2CO3/ CaCl210. 000. 005000. 000. 00-5. 8113. 07144. 47 20. 500. 00500-58. 13-11. 63 Appendix B Sample Calculations Calibration of Calorimeter 10ml 1M NaOH + 5ml 1M HCl n. i. e. : OH-(aq) + H+(aq) ? H2O(l)? Horxn= -55. 8kJ LR: HCLnLR= 0. 005mol Grp 1 Trial 1 ?T= 2. 2oC Sol’n: C_cal=(- H? _rxn^o n_LR)/? T C_cal=(-(-55. 8kJ)(0. 005mol))/(? 2. 2? ^ o C)? 1000J/1kJ ?(C_cal=126. 82 J) Determination of Heats of Reaction Neutralization Reaction Rxn 4 Trial 1: 10ml 1M NaOH + 5ml 1M HNO3 n. i. e. : OH-(aq) + H+(aq) ? H2O(l) LR: HNO3nLR= 0. 005mol ?T= 1. 5oCCcal= 244. 125 J Sol’n H? _rxn^o=(-C_cal ? T)/n_LR H? _rxn^o=(-(244. 25J)(? 1. 5? ^o C))/0. 005mol? 1kJ/1000J ? ( H? _rxn^o=-73. 24kJ) Reaction between an Active Metal and an Acid Rxn 5 Trial 1: 15ml 1M HCl+ 0. 05g Mg n. i. e. : 2H+(aq) + Mg(s) ? Mg+2(aq) + H2(g) LR: MgnLR= 0. 00206mol ?T= 3oCCcal= 81. 375 J Sol’n H? _rxn^o=(-C_cal ? T)/n_LR H? _rxn^o=(-(81. 375J)(3^o C))/0. 00206mol? 1kJ/1000J ?( H? _rxn^o=-118. 67kJ) Displacement of One Metal by Another Rxn 7 Trial 1: 15ml 1M CuSO4 + 0. 5g Zn n. i. e. : Cu+2(aq) + Zn(s) ? Zn+2(aq) + Cu(s) LR: ZnnLR= 0. 00764mol ?T= 3oCCcal= 111. 6 J Sol’n H? _rxn^o=(-C_cal ? T)/n_LR H? _rxn^o=(-(111. 6J)(3^o C))/0. 00764mol? 1kJ/1000J ?( H? rxn^o=-43. 80kJ) Precipitation Reaction Rxn 8 Trial 1: 10ml 0. 5M Na2CO3 + 5ml 1M CaCl2 n. i. e. : CO3-2(aq) + Ca+2(aq) ? CaCO3(s) LR: Na2CO3/ CaCl2nLR= 0. 005mol ?T= 0. 5oCCcal= 116. 25 J Sol’n H? _rxn^o=(-C_cal ? T)/n_LR H? _rxn^o=(-(116. 25J)(? 0. 5? ^o C))/0. 005mol? 1kJ/1000J ? ( H? _rxn^o=-11. 63kJ) Appendix C Answers to the Questions in the Lab Manual There are many possibilities that explain the discrepancy of the experimental and theoretical values of ? Horxn. First, heat might have been lost to the surroundings. This is possible whenever the thermometer is pulled out or pushed in the calorimeter during the reaction. Also, the calorimeter might not have been thoroughly isolated. Second, the solution might have been diluted in the test tube or pipette. They might have been wet when used with the solution. Lastly, the discrepancies might have occurred due to human error. The students might have misread the thermometer when taking the temperature or the pipette when measuring the solutions. a. It is important to keep the total volume of the resulting solution to 15ml because any more or any less than that of the volume can contribute to the absorption or release of additional heat therefore affecting the ? Horxn. b. It is important to know the exact concentrations of the reactants to solve for their number of moles and to find out the limiting reactant. c. It is important to know the exact weight of the metal solids used to solve for their number of moles and to find out whether one of them is a limiting reactant. Also, the weight is needed to solve for the heat capacity of the solid when the specific heat is given. 200ml 0. 5M HA + NaOH ? -6. 0kJ LR: HAnLR= 0. 1mole H? _(rxn,mol)^o= (-6. 0 kJ)/(0. 1 mol) ?( H? _(rxn,mol)^o= -60 kJ) HA is a strong acid. OH-(aq) + H+(aq) ? H2O(l)? Horxn= -60 kJ/mole Calibration:15ml 2. M HCl + 5ml 2. 0M NaOH? T=5. 60oC LR: NaOHnLR= 0. 01mole Reaction:20ml 0. 450M CuSO4 + 0. 264g Zn? T=8. 83oC LR: ZnnLR= 0. 00404mole n. i. e. : OH-(aq) + H+(aq) ? H2O(l) n. i. e. : Cu+2(aq) + Zn(s) ? Zn+2(aq) + Cu(s) C_cal=(- H? _rxn^o n_LR)/? T C_cal=(-(-55. 8kJ)(0. 01mol))/(? 5. 60? ^o C)? 1000J/1kJ ?(C_cal=99. 6 J) H? _rxn^o=(-C_cal ? T)/n_LR H? _rxn^o=(-(99. 6J)(? 8. 83? ^o C))/0. 00404mol? 1kJ/1000J ? ( H? _rxn^o=-218. 0 kJ) OH-(aq) + H+(aq) ? H2O(l)? Horxn= -55. 8kJ ?Hof,H2O= -285 kJ ?Hof,OH-= ? ?Horxn= ? Hof,product – ? Hof,reactant -55. 8 kJ = ? Hof,OH- – (-285 kJ) ?( H? _(f,? OH? ^-)^o=-218. 0 kJ)

Lamo to the slaughter Assignment Example | Topics and Well Written Essays - 250 words

Lamo to the slaughter - Assignment Example As regards the giggle, she seems contented of her actions. When Patrick arrives home, one can witness that something is wrong from several instances. This is demonstrable by the way he gulps his whisky in one swing (Dahl 28). In addition, he declines the offer of food from Mary (Dahl 30). Patrick says â€Å"this is going to be a bit of a shock to you.† This news might entail information about a break up. Mary could not accept the message. She acts as if she is striving to please Patrick. When Mary realizes that she has murdered her husband, the same astound her. Mary strives to act normal by having a make-up. She then goes to the grocery in order to fool Sam that everything was normal in the house. In this sense, Sam would easily act as a witness to her favor. She then goes back to the house and wails whereby police officers and detectives come in to address the scenario. The police’s investigation of Patrick’s death is bias in the sense that they believe an external party would have been responsible for the same. There is cheese and pork lying on the floor. Mary Maloney is holding Patrick’s body as she cries. In addition, Patrick’s body lies on the floor while facing the roof. There are signs of blood on Patrick’s head. The first witness is Mary Maloney. She reports that Patrick acted quite normal and drunk his usual whiskey. She says that she placed pork in the oven and went out to look for vegetables. When she retreated in the house, she found Patrick lying on the floor. Thereafter, she realizes that Patrick

PROMOTING BETTER PATIENT CARE Essay Example | Topics and Well Written Essays - 500 words

PROMOTING BETTER PATIENT CARE - Essay Example Speech-language pathologists are certified by the American Speech-Language-Hearing Association (ASHA) and hold the masters degree or the degree certified to be suitable for the role. (McKay, 2012a, p.1) The speech therapists role is to guide and simulate the process of recovery by means of speech and language exercises. Autism, cleft palate, brain or damage disorders, voice disorder, stammering are some of the causes for the speech difficulties. There are normal swallowing and speech changes after the head and neck cancer treatment and they need assistance of the speech pathologist. (â€Å"Encyclopedia of Health†, 2010, p. 977) A social worker help patients and families cope up with the problem resulting from long term illness, injury and rehabilitation. ‘Medical and public health social worker provide psychosocial support to those affected by chronic, acute, or terminal illnesses. They work with patients, families, and caregivers.’(Mc Kay, 2012b, p. 1)The Council on Social Work Education accredits the baccalaureate and master’s degree programs in social work in the United States. (Zastrow, p. xx) Communication is an important tool for the speech therapists as it enables them to interact with the patient and develop the confidence in them. The treatment varies according to its severity and is based upon the patient’s case history and also relies on the patient’s verbal report of symptoms. There is a major concern in the availability of speech therapists and if the facility did not have this specialty, then the use of interdisciplinary team concept is appropriate. It is a group of health care professionals from diverse fields who work in a coordinated fashion toward a common goal for the patient.(â€Å"Interdisciplinary teams†, Medical Dictionary) The team includes mostly the individual with severe communication disabilities, a family member or guardian, a speech-language pathologist,

The Organization of African Unity Known as African Union Research Paper - 1

The Organization of African Unity Known as African Union - Research Paper Example So, the role of African Union within the African context is important because it promotes positive change in the society by empowering the people and solving problems. Thesis statement: The organizational setup, responsibilities and social services provided by the African Union proves to be successful within the scenario of social work in Africa (special references to the social services provided by African Union in Africa and its involvement in current issues).   Ã‚  Ã‚  Ã‚  Ã‚   First of all, almost all the African nations have membership in African Union (AU). For instance, excluding Morocco, present strength of the African Union is 53. African Union, a social work organization for creating unity among the African nations was established in the year 2002. Besides, the Organisation of Africa Unity (AOU) was the mother organization of AU. Okoth (2006) opines that â€Å"Some of the guiding principles of the AU are similar to those of its predecessor, the OAU† (p. 325). The organizational set-up of AU is based on centralization and concentration of power which is fully vested in the center but with equal power to the member states. For instance, the decision-making force of AU is the Assembly of the African Union. Badejo (2008) states that â€Å"The AU carries out its business through many organs, agencies, and non-governmental organizations† (p. 39). The Secretariat (say, African Union Commission) of AU is in Addis Ababa, whi ch is situated in Ethiopia.  Ã‚  Ã‚  Ã‚     Ã‚  Ã‚  Ã‚  Ã‚   The AU is divided into two bodies: political and administrative.  Ã‚   As pointed out, the decision-making process is principally vested upon the Assembly, which consists of members/representatives from member states. The present chairman is Bingu Mutharika, who represents Malawi. Besides, the representative body of AU, namely Pan African Parliament includes 265 members. Idriss Ndele Moussa is the present president of Pan African Parliament.